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leetcode 004.寻找两个有序数组的中位数
阅读量:110 次
发布时间:2019-02-26

本文共 2012 字,大约阅读时间需要 6 分钟。

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  • ??????O(m + n)??????????????
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  • ????????????k?????k?(m + n)/2?(m + n)/2 + 1?
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    • ?????index1?index2??????????????
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  • ??????O(log(m + n))???????????????
  • ??????O(1)?????????????????
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  • ??????O(log(m + n))???????????
  • ??????O(1)?????????????????
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    class Solution {    public double findMedianSortedArrays(int[] nums1, int[] nums2) {        int len1 = nums1.length, len2 = nums2.length;        int totalLength = len1 + len2;        if (totalLength % 2 == 1) {            int midIndex = totalLength / 2;            return getKthElement(nums1, nums2, midIndex + 1);        } else {            int midIndex1 = totalLength / 2 - 1;            int midIndex2 = totalLength / 2;            double median = (getKthElement(nums1, nums2, midIndex1 + 1) + getKthElement(nums1, nums2, midIndex2 + 1)) / 2.0;            return median;        }    }    public int getKthElement(int[] nums1, int[] nums2, int k) {        int l1 = nums1.length, l2 = nums2.length;        int i = 0, j = 0;        while (true) {            if (i == l1) return nums2[j + k - 1];            if (j == l2) return nums1[i + k - 1];            if (k == 1) return Math.min(nums1[i], nums2[j]);            int half = k / 2;            int ni1 = Math.min(i + half, l1) - 1;            int ni2 = Math.min(j + half, l2) - 1;            int p1 = nums1[ni1], p2 = nums2[ni2];            if (p1 <= p2) {                k -= (ni1 - i + 1);                i = ni1 + 1;            } else {                k -= (ni2 - j + 1);                j = ni2 + 1;            }        }    }}

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